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Sagot :
2 5 dollar bills
10 10 dollar bills
ammount of 5 dollar bills= x
amount of 10 dollar bills = y
5x=y
x+y=12
x+5x=12
6x=12
x=2
12-x=y
12-2=y
10=y
10 10 dollar bills
ammount of 5 dollar bills= x
amount of 10 dollar bills = y
5x=y
x+y=12
x+5x=12
6x=12
x=2
12-x=y
12-2=y
10=y
There are two $5 bills and ten $10 bills in Neil's wallet and this can be determined by forming the linear equation in two variables.
Given :
- Neil has a total of twelve $5 and $10 bills in his wallet.
- Neil has 5 times as many $10 bills as $5 dollar bills.
Let the total number of $5 bills be 'a' and the total number of $10 bills be 'b'. Then the total number of bills will be:
[tex]a+b = 12[/tex] --- (1)
It is given that Neil has 5 times as many $10 bills as $5 dollar bills, that is:
[tex]5a = b[/tex] ---- (2)
Now, substitute the value of 'b' in equation (1).
a + 5a = 12
6a = 12
a = 2
Now, put the value of 'a' in equation (2).
[tex]5\times 2 = b[/tex]
b = 10
There are two $5 bills and ten $10 bills in Neil's wallet.
For more information, refer to the link given below:
https://brainly.com/question/13738061
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