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find the sum of 3b/b+2 and 12/b+2 and express it in simplest form

Sagot :

[tex]\frac{3b}{b+2}+\frac{12}{b+2}=\frac{3b+12}{b+2}\\\\\\\frac{3b+12}{b+2}=\frac{3b+6+6}{b+2}=\frac{3b+6}{b+2}+\frac{6}{b+2}=\frac{3(b+2)}{b+2}+\frac{6}{b+2}=3+\frac{6}{b+2}[/tex]
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