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a 16.0g sample of iron was heated from 0 degrees Celsius o 35.0 degrees Celsius.the iron absorbed 246.4J of energy as heat. what is the specific heat of this piece of iron?

Sagot :

lulu1991
Specific heat means the amount heat needed when unit mass of a substrate increase one degree of temperature. So the specific heat = the heat absorbed/(the mass of the substrate * change in temperature) = 264.4/(16*35)=0.472 J/(g*℃）

Answer: [tex]0.44J/g^0C[/tex]

Explanation:

Specific heat capacity of a substance is defined as the amount of heat required to raise the temperature of 1g of substance through [tex]1^0C[/tex]

[tex]Q= m\times c\times \Delta T[/tex]

Q= heat gained  = 246.4 J

m= mass of the substance = 16 g

c = heat capacity of  iron= ? J/g ° C      

[tex]\Delta T={\text{Change in temperature}}=(35-0)^oC=35^0C[/tex]  

[tex]246.4=16g\times cJ/g^oC\times 35^oC[/tex]

[tex]c=0.44J/g^0C[/tex]

Thus specific heat capacity of iron is [tex]0.44J/g^0C[/tex]

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