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roll the die twice. what is the probability of rolling a 6 on the 1st roll? an odd number on the 2nd roll?

Sagot :

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The probability of rolling a 6 on the 1st roll is [tex] \frac{1}{6} [/tex], since there is only 1 out of 6 sides of the dice that has six pips.

The probability of rolling an odd number is [tex] \frac{1}{2} [/tex], since there are 3 out of 6 sides of the dice that has an odd number of pips. [tex] \frac{3}{6} = \frac{1}{2}[/tex]

Then the probablity of both events happening one after another is [tex] \frac{1}{12} [/tex]. You have to multiply both probabilities of the events: [tex] \frac{1}{6} * \frac{1}{2} = \frac{1}{12}[/tex]


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