BlossomFlower
Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Simplify.
Please give an explanation or step-by-step answer.

SimplifyPlease Give An Explanation Or Stepbystep Answer class=

Sagot :

konrad509
[tex]\dfrac{2y}{y^2-9y+18}-\dfrac{1}{y-6}=\\ \dfrac{2y}{y^2-3y-6y+18}-\dfrac{1}{y-6}=\\ \dfrac{2y}{y(y-3)-6(y-3)}-\dfrac{1}{y-6}=\\ \dfrac{2y}{(y-6)(y-3)}-\dfrac{1}{y-6}=\\ \dfrac{2y}{(y-6)(y-3)}-\dfrac{y-3}{(y-6)(y-3)}=\\ \dfrac{2y-y+3}{(y-6)(y-3)}=\\ \dfrac{y+3}{(y-6)(y-3)}[/tex]
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.