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how do i calculate (Log)23+(log)93?

Sagot :

a property of logs, is
log ab=log a+log b so

log 23+log 93=log (23 times 93)=log 2139
assuming log to base 10 you would be solving for
10^x=2139
this is the same as
log 2139
not sure how to solve it except by puting it into a calculator or looking it up on a log table
the answer is aprox 3.3302107845715