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write an equation in standard form with integer coefficients for the line with slope 6/11 going through the point (-1,-6)

Sagot :

If the slope is 6/11 then, in y=mx+b form, m will be 6/11.  When you multiply 6/11 and -1 you get -6/11.  To get the y (-6), you have to add -60/11.  So in, y=mx+b form the equation is y=6/11x+(-60/11).  To make it standard form, you add negative 6/11x to both sides and then multiply by 11 to get rid of the fractions. So therefore the equation would be:

-6x + 11y = - 60
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