Answered

At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

what is the area of a rectangle with a length of (x^2-2) and a width of(2x-x+2)

Sagot :

a386
The area of a rectangle can be found through the formula [tex]A=lw[/tex], where l is the length and w is the height.  In this situation, the answer can be found by multiplying the length and width provided:

[tex](x^2-2)*(2x-x+2)[/tex]

The distributive property must be applied here:

[tex](x^2-2)*(2x-x+2) \\ 2x^3-x^3+2x^2-4x+2x-4[/tex]

Now simplify by combining like terms:

The area is
[tex] x^3+2x^2-2x-4[/tex]
Panoyin
A = lw
A = (x² - 2)(2x - x + 2)
A = (x² - 2)(x + 2)
A = x²(x + 2) - 2(x + 2)
A = x²(x) + x²(2) - 2(x) - 2(2)
A = x³ + 2x² - 2x - 4
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.