Answered

Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

what is the area of a rectangle with a length of (x^2-2) and a width of(2x-x+2)

Sagot :

a386
The area of a rectangle can be found through the formula [tex]A=lw[/tex], where l is the length and w is the height.  In this situation, the answer can be found by multiplying the length and width provided:

[tex](x^2-2)*(2x-x+2)[/tex]

The distributive property must be applied here:

[tex](x^2-2)*(2x-x+2) \\ 2x^3-x^3+2x^2-4x+2x-4[/tex]

Now simplify by combining like terms:

The area is
[tex] x^3+2x^2-2x-4[/tex]
Panoyin
A = lw
A = (x² - 2)(2x - x + 2)
A = (x² - 2)(x + 2)
A = x²(x + 2) - 2(x + 2)
A = x²(x) + x²(2) - 2(x) - 2(2)
A = x³ + 2x² - 2x - 4
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.