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What are the roots of -12x2 + 11x − 3 = 0?

Sagot :

Panoyin
-12x² + 11x - 3 = 0
x = -(11) +/- √((11)² - 4(-12)(-3))
                        2(-12)
x = -11 +/- √(121 - 144)
                   -24
x = -11 +/- √(-23)
              -24
x = -11 +/- i√(23)
             -24
x = -11 + i√(23)                x = -11 - i√(23)
            -24                                   -24
x = ¹¹/₂₄ - 0.0416√(23)      x = ¹¹/₂₄ + 0.0416√(23)
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