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use a method of completing the square in order to rewrite the function f(x)=x^2+5x-2 in vertex form, f(x)=a(x-h)^2+k where (h,k) is the vertex of the parabola.

Sagot :

      f(x) = x² + 5x - 2
f(x) + 2 = x² + 5x - 2 + 2
f(x) + 2 = x² + 5x
f(x) + 2 = x(x) + x(5)
f(x) + 2 = x(x + 5)
      f(x) = x(x + 5) - 2
   (h, k) = (-5, 2)

The function in vertex form is [tex](x-\frac{5}{2} )^{2} -\frac{33}{4}[/tex] and the vertex (h,k) is (-2.5,-8.25).

What is Completing the Square method?

Completing the Square is a technique which can be used to find maximum or minimum values of quadratic functions. It is a method used to solve a quadratic equation by changing the form of the equation so that the left side is a perfect square trinomial .

For the given situation,

The function is f(x)=x^2+5x-2.

Plot this function on the graph as shown, this gives the vertex of the function.

The vertex of the function using completing the square method is

⇒ [tex]f(x)=x^2+5x-2[/tex]

Take the coefficient of x and perform the operation,

⇒ [tex](\frac{5}{2}) ^{2} = \frac{25}{4}[/tex]

Now add and subtract this value in the above equation,

⇒ [tex](x^{2} +5x+\frac{25}{4} )-2-\frac{25}{4}[/tex]

⇒ [tex](x-\frac{5}{2} )^{2} -\frac{33}{4}[/tex]

On comparing this equation with the equation in vertex form, we get

⇒ [tex]h=\frac{-5}{2}=-2.5[/tex] and

⇒ [tex]k=-\frac{33}{4}=-8.25[/tex]

⇒ [tex]a=1[/tex]

Hence we can conclude that the function in vertex form is [tex](x-\frac{5}{2} )^{2} -\frac{33}{4}[/tex] and the vertex (h,k) is (-2.5,-8.25).

Learn more about completing the square method here

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