Answered

Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

In a certain lottery, the winner of the first ticket drawn receives $10. Each succeeding ticket drawn is worth $15 more than the previous ticket. How much does the holder of the tenth ticket drawn receive?

Sagot :

AL2006
The value of each winning ticket is an arithmetic series in which T (n) = -5 + 15n or $5 (3n-1). The first winner is 5 (3x1 - 1) = $10. The second winner is 5 (3x2 - 1) = $25. The tenth ticket wins $5 (3x10 - 1) = $5 (29) = $145.
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.