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what is the sum of the first 100 positive multiples of 4?

Sagot :

 This would be a series: 5 + 10 + 15 + 20 +...+ 500
there are n terms → n = 100
the nth term is 500

sum = (n/2)(a+b) in which n=number of multiples a = value of first multiple b = value of last multiple So : (100/2) X (4+400) 50 X 404 20200  The final answer is 20200. You got it?