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Sagot :
x = 5 - 3y
x = 2y - 10
5 - 3y = 2y - 10
+ 3y + 3y
5 = 5y - 10
+ 10 + 10
15 = 5y
5 5
3 = y
x = 2y - 10
x = 2(3) - 10
x = 6 - 10
x = -4
(x, y) = (-4, 3)
x = 2y - 10
5 - 3y = 2y - 10
+ 3y + 3y
5 = 5y - 10
+ 10 + 10
15 = 5y
5 5
3 = y
x = 2y - 10
x = 2(3) - 10
x = 6 - 10
x = -4
(x, y) = (-4, 3)
y=3
x=-4
you have to use substitution. so instead of the equations having two variables, they will now have one.
5-3y=2y-10 after solving for y, plug the answer in any of the equations and you will find x.
x=-4
you have to use substitution. so instead of the equations having two variables, they will now have one.
5-3y=2y-10 after solving for y, plug the answer in any of the equations and you will find x.
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