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Sagot :
A slope of -3 can be written as a fraction of -3 over 1.
In terms of rise over run, that means when we subtract 3 from y we add 1 to x.
So plot (1, 3), then go down 3 and over 1 and plot that point.
Make a line between them and you're done.
In terms of rise over run, that means when we subtract 3 from y we add 1 to x.
So plot (1, 3), then go down 3 and over 1 and plot that point.
Make a line between them and you're done.
You use the point slope formula which is (y-y sub 1) = slope(x- x sub 1)
So it would be (y-3)=-3(x-1). Distribute -3 to x-1.
y-3=-3x+3. Add 3 to both sides. It will then equal y=-3x+6. First graph the y-intercept which is six then go down three over 1 because the slope is -3 which is the same -3/1. I hope this helps!
So it would be (y-3)=-3(x-1). Distribute -3 to x-1.
y-3=-3x+3. Add 3 to both sides. It will then equal y=-3x+6. First graph the y-intercept which is six then go down three over 1 because the slope is -3 which is the same -3/1. I hope this helps!
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