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solve by factoring 7b^2-8b+3=2

Sagot :

AyaZ
[tex]7b^2-8b+3=2 \\ 7b^2-8b+1=0 \\ (7x-1)(x-1)=0 \\ x=1 \\ x= \frac{1}{7} [/tex]
charity09
Subtract the 2 over from the 3 which leaves you with 1 as the constant. Then you have 7b^2-8b+1. Slide the 7 over to the 1 using the slide and divide method. This leaves you with b^2-8b+7. Then just think "what multiplies to get 7, and adds to -8." The answer to that is (x-7)(x-1). Then you have to divide by 7 because you slid it earlier. So that gives you the answer of : (x-1)(7x-1).
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