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We want to find how much charge is on the electrons in a nickel coin. Follow this method. A nickel coin has a mass of about 5.7 g.
a. Find the number of atoms in a nickel coin. Each mole (6.02 × 10^23 atoms) has a mass of about 57.9 g. Answer in units of atoms.
b. Find the number of electrons in the coin. Each nickel atom has 28 electrons/atom. Answer in units of electrons.
c. Find the magnitude of the charge of all these electrons. Answer in units of C.

Sagot :

bufjasmine
5.6x10e22 atoms
Hope I helped, and good luck!

The number of atoms in a metal the product of weight of the atom of the metal and Avagardo's number divided by atomic mass.

  • The number of atom in a nickel coin with mass 5.7 kg is [tex]5.93\times 10^{22}[/tex] atoms.
  • The number of electrons in nickel coin is [tex]1.66\times 10^{24}[/tex] atoms.
  • The magnitude of the charge of all these electrons is  [tex]e=2.656\times10^{5}[/tex] C.

Given information-

The mass of the nickel coin is 5.7 g.

  • A)  The number of atoms in a nickel coin.

How to find number of atom in metal?

The number of atoms in a metal the product of weight of the atom of the metal and Avagardo's number divided by atomic mass.

As each mole (6.02 × 10^23 atoms) has a mass of about 57.9 g.

Thus the number of atom in a nickel coin with mass 5.7 kg,

[tex]n=\dfrac{5.7}{57.9} \times6.02\times 10^{23}[/tex]

[tex]n=5.93\times 10^{22}[/tex]

Hence  the number of atom in a nickel coin with mass 5.7 kg is [tex]5.93\times 10^{22}[/tex] atoms.

  • B) Number of electrons in the coin.

As each nickel atom has 28 electrons/atom and total number of atom in a nickel coin with mass 5.7 kg is [tex]5.93\times 10^{22}[/tex] atoms. Thus number of electrons in the coin in nickel coin is,

[tex]q=5.93\times10^{22}\times28\\q=1.66\times 10^{24}[/tex]

Hence the number of electrons in nickel coin is [tex]1.66\times 10^{24}[/tex] atoms.

  • C) The magnitude of the charge of all these electrons-

Magnitude of the each electron, is [tex]1.6\times10^{-19}[/tex]. Thus the magnitude of the charge of all these electrons is,

[tex]e=1.66\times 10^{24}\times1.6\times10^{-19}\\e=2.656\times10^{5}[/tex]

Thus the magnitude of the charge of all these electrons is  [tex]e=2.656\times10^{5}[/tex] C.

Hence,

  • The number of atom in a nickel coin with mass 5.7 kg is [tex]5.93\times 10^{22}[/tex] atoms.
  • The number of electrons in nickel coin is [tex]1.66\times 10^{24}[/tex] atoms.
  • The magnitude of the charge of all these electrons is  [tex]e=2.656\times10^{5}[/tex] C.

Learn more about the atomic number here;

https://brainly.com/question/2099804

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