JonellWhitemore632
Answered

Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

We want to find how much charge is on the electrons in a nickel coin. Follow this method. A nickel coin has a mass of about 5.7 g.
a. Find the number of atoms in a nickel coin. Each mole (6.02 × 10^23 atoms) has a mass of about 57.9 g. Answer in units of atoms.
b. Find the number of electrons in the coin. Each nickel atom has 28 electrons/atom. Answer in units of electrons.
c. Find the magnitude of the charge of all these electrons. Answer in units of C.

Sagot :

bufjasmine
5.6x10e22 atoms
Hope I helped, and good luck!

The number of atoms in a metal the product of weight of the atom of the metal and Avagardo's number divided by atomic mass.

  • The number of atom in a nickel coin with mass 5.7 kg is [tex]5.93\times 10^{22}[/tex] atoms.
  • The number of electrons in nickel coin is [tex]1.66\times 10^{24}[/tex] atoms.
  • The magnitude of the charge of all these electrons is  [tex]e=2.656\times10^{5}[/tex] C.

Given information-

The mass of the nickel coin is 5.7 g.

  • A)  The number of atoms in a nickel coin.

How to find number of atom in metal?

The number of atoms in a metal the product of weight of the atom of the metal and Avagardo's number divided by atomic mass.

As each mole (6.02 × 10^23 atoms) has a mass of about 57.9 g.

Thus the number of atom in a nickel coin with mass 5.7 kg,

[tex]n=\dfrac{5.7}{57.9} \times6.02\times 10^{23}[/tex]

[tex]n=5.93\times 10^{22}[/tex]

Hence  the number of atom in a nickel coin with mass 5.7 kg is [tex]5.93\times 10^{22}[/tex] atoms.

  • B) Number of electrons in the coin.

As each nickel atom has 28 electrons/atom and total number of atom in a nickel coin with mass 5.7 kg is [tex]5.93\times 10^{22}[/tex] atoms. Thus number of electrons in the coin in nickel coin is,

[tex]q=5.93\times10^{22}\times28\\q=1.66\times 10^{24}[/tex]

Hence the number of electrons in nickel coin is [tex]1.66\times 10^{24}[/tex] atoms.

  • C) The magnitude of the charge of all these electrons-

Magnitude of the each electron, is [tex]1.6\times10^{-19}[/tex]. Thus the magnitude of the charge of all these electrons is,

[tex]e=1.66\times 10^{24}\times1.6\times10^{-19}\\e=2.656\times10^{5}[/tex]

Thus the magnitude of the charge of all these electrons is  [tex]e=2.656\times10^{5}[/tex] C.

Hence,

  • The number of atom in a nickel coin with mass 5.7 kg is [tex]5.93\times 10^{22}[/tex] atoms.
  • The number of electrons in nickel coin is [tex]1.66\times 10^{24}[/tex] atoms.
  • The magnitude of the charge of all these electrons is  [tex]e=2.656\times10^{5}[/tex] C.

Learn more about the atomic number here;

https://brainly.com/question/2099804

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.