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Sagot :
The surface area = The area of the two bases + the area of the lateral surface
The area of 1 base = 24 mm², so the area of two is 48 mm².
The area of the lateral surface = the perimeter of the base × the height.
The perimeter = 22 mm. The height = 5 mm.
Thus the lateral surface area is 110 mm².
The total surface area is 110 + 48 = 158 mm².
The area of 1 base = 24 mm², so the area of two is 48 mm².
The area of the lateral surface = the perimeter of the base × the height.
The perimeter = 22 mm. The height = 5 mm.
Thus the lateral surface area is 110 mm².
The total surface area is 110 + 48 = 158 mm².
The surface area = The area of the two bases + the area of the lateral surface
The area of 1 base = 24 mm², so the area of two is 48 mm².
The area of the lateral surface = the perimeter of the base × the height.
The perimeter = 22 mm. The height = 5 mm.
Thus the lateral surface area is 110 mm².
The final answer is 158mm to the power of 2
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