Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Given the size and mass of each of the solid cubes X and Y, how many
times is the density of cube X greater than the density of cube Y?

Sagot :

Blade678
since 
density = mass/volume (which is just another word for size)

density of cube X = (cube X's mass) / (cube X's volume)
lets name "(cube X's mass) / (cube X's volume)" as "x"

density of cube Y = (cube Y's mass) / (cube Y's volume)
lets name "(cube Y's mass) / (cube Y's volume)" as "y"

then to calculate how many times is the density of cube X to density of cube Y, then it will be x/y

if calculating how many times greater, then it is (x-y)/y

though the phrase "how many times greater" can also mean "how many times". 
flowergirllilly18

Answer:

D 16

Step-by-step explanation:

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.