Answered

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A party rental company has chairs and tables for rent .the total cost to rent 8 chairs and 4 tables is $53 the total cost to rent 3 chairs and 2 tables is $24 what is the cost to rent a chair and each table

Sagot :

mumsy
In order to solve this problem, we will let be
c= chairs, t=tables and have the following equations
8c+4t=53
3c+2t=24
we can solve this system by multiplying the second equation with -2 and add it to the first one
8c+4t=53
-6c-4t=-48
we add them and get
2c=5,  therefore c=5/2=2.5 , so to rent a chair you need to pay 2.50 dollars
now we will replace c with 2.50
  3*(2.50)+2t=24
7.50+2t=24  subtract 7.50 from both sides
2t=24-7.50
2t=16.50
t=16.50/2=8.25        8.25 to rent a table

we want to verify our answer
8(2.50)+4(8.25)=20+33=53  
correct!!!!!


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