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The distance traveled by a falling rock is modeled by d=5t^2, where d is the distance in meters and t is the time in seconds. Write and simplify an expression for the distance the rock falls at 2t seconds. Is it twice as far? Explain your reasoning.

Sagot :

Zacharias
So given [tex]d=5t^2[/tex], you need to substitute 2t as t, [tex]5(2t)^2[/tex]. Simplify the equation; [tex]5(4t^2)[/tex] and then to [tex]20t^2[/tex]. when you plug in values for time, lets say 4, the distance traveled quadruples.
[tex]d=5(4)^2[/tex]
[tex]d=80m[/tex]
[tex]d=5(20)^2[/tex]
[tex]d=320m[/tex]
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