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wht is the sum of 3b/b+2and12

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Panoyin
[tex]\frac{3b}{b + 2} + 12 = \frac{3b}{b + 2} + \frac{12(b + 2)}{1(b + 2)} = \frac{3b}{b + 2} + \frac{12b + 24}{b + 2} = \frac{15b + 24}{b + 2} = \frac{3(5b + 8)}{b + 2}[/tex]
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