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Sagot :
the way to find the area of a triangle is A=[tex] \frac{B*H}{2} [/tex]
if the base is 3 feet longer then the height we can write it like this B=H+3
now we can add it to our area equation
20=[tex] \frac{H(H+3)}{2} [/tex]
20=[tex] \frac{ h^{2} +3h}{2} [/tex]
40=[tex] H^{2} [/tex]+3H
10[tex] \frac{1}{3} [/tex]=[tex] H^{2} [/tex]
h=3.2ft
if the base is 3 feet longer then the height we can write it like this B=H+3
now we can add it to our area equation
20=[tex] \frac{H(H+3)}{2} [/tex]
20=[tex] \frac{ h^{2} +3h}{2} [/tex]
40=[tex] H^{2} [/tex]+3H
10[tex] \frac{1}{3} [/tex]=[tex] H^{2} [/tex]
h=3.2ft
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