Answered

Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get quick and reliable solutions to your questions from a community of experienced professionals on our platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Write the standard form of each circle
Ends of diameter :(-16,-8) (12,4)

Sagot :

AL2006

The ends of the diameter are  (-16, -8) and (12,4)

The point midway between those points is

        x = (1/2) (-16+12) = (1/2) (-4)  =  -2
      
       y = (1/2) (-8+4) = (1/2) ( -4)  =  -2

So the point (-2, -2) is the center of the circle.


The ends of the diameter are  (-16, -8) and (12,4)

The distance between those points is . . .

         the square root of (12+16)² + (4+8)²  =

                   square root of  (28)² + (12)² =

                   square root of  (784 + 144) =

                   square root of    (928)    

The diameter of the circle is  √928 ,
             so its radius is (1/2)√928  =  √232 .

Now that we know the center and the radius,
we can write the equation of the circle:

               (x + 2)² + (y + 2)²  =  232




         



Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.