Answered

Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Write the standard form of each circle
Ends of diameter :(-16,-8) (12,4)

Sagot :

AL2006

The ends of the diameter are  (-16, -8) and (12,4)

The point midway between those points is

        x = (1/2) (-16+12) = (1/2) (-4)  =  -2
      
       y = (1/2) (-8+4) = (1/2) ( -4)  =  -2

So the point (-2, -2) is the center of the circle.


The ends of the diameter are  (-16, -8) and (12,4)

The distance between those points is . . .

         the square root of (12+16)² + (4+8)²  =

                   square root of  (28)² + (12)² =

                   square root of  (784 + 144) =

                   square root of    (928)    

The diameter of the circle is  √928 ,
             so its radius is (1/2)√928  =  √232 .

Now that we know the center and the radius,
we can write the equation of the circle:

               (x + 2)² + (y + 2)²  =  232




         



We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.