Answered

Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Write the standard form of each circle
Ends of diameter :(-16,-8) (12,4)

Sagot :

AL2006

The ends of the diameter are  (-16, -8) and (12,4)

The point midway between those points is

        x = (1/2) (-16+12) = (1/2) (-4)  =  -2
      
       y = (1/2) (-8+4) = (1/2) ( -4)  =  -2

So the point (-2, -2) is the center of the circle.


The ends of the diameter are  (-16, -8) and (12,4)

The distance between those points is . . .

         the square root of (12+16)² + (4+8)²  =

                   square root of  (28)² + (12)² =

                   square root of  (784 + 144) =

                   square root of    (928)    

The diameter of the circle is  √928 ,
             so its radius is (1/2)√928  =  √232 .

Now that we know the center and the radius,
we can write the equation of the circle:

               (x + 2)² + (y + 2)²  =  232




         



Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.