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Sagot :
[tex]P=1.48 \ km = 1 \ 480 \ m \\ \\1 \ km = 1000 \ m \\ \\ l=460 \ m \\ \\ it \ has \ perimeter : \\ \\ P = 2 \cdot l + 2\cdot w \\ \\1480=2*460 + 2w \\ \\1480=920 +2w\\ \\ 2w=1480-920\\ \\2w=560 \ \ /:2 \\ \\w=280 \ m \\ \\Answer : \ field \ has \ a \ width : \ 280 \ m[/tex]
P = 1.48km = 1480m
P = 2l + 2w
l = 460
2l = 920
1480 - 920 = 560
560 = 2w
560 ÷ 2 = 280
280m = width or w
P = 2l + 2w
l = 460
2l = 920
1480 - 920 = 560
560 = 2w
560 ÷ 2 = 280
280m = width or w
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