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square root of 64 over 25

Sagot :

so [tex] \sqrt{\frac{64}{25} } [/tex]

that is equal to  [tex]\frac{ \sqrt{64}}{ \sqrt{25}} = \frac{8}{5} [/tex]
**Refresh page if you see [ tex ]**

Knowing that [tex]64 = 8^2\quad\text{and}\quad25 = 5^2[/tex], we have

[tex] \sqrt{\dfrac{64}{25}} = \dfrac{\sqrt{64}}{\sqrt{25}} = \boxed{\dfrac{8}{5}}[/tex]