Answered

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the amount of charge that moves through the filament of a lightbulb in 2.00 s is 2.67 C. what is the current of the lightbulb?

Sagot :

AL2006

The electric "current" in a conductor is the rate at which
charge flows through it.

Current = (charge) / (time)

Current = (2.67 Coulombs) / (2 seconds)  =

                 1.335 Coulombs per second =  

                         1.335 Amperes


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