AbigailOpula610
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Identify the first and last term of the binomial expansion for the problem below. (3 + 2a)5 = _____ + … + _____ Can someone please help me solve this?? I'm on a time limit.

Sagot :

Panoyin
(3 + 2a)⁵
(3 + 2a)(3 + 2a)(3 + 2a)(3 + 2a)(3 + 2a)
(3(3 + 2a) + 2a(3 + 2a))(3(3 + 2a) + 2a(3 + 2a))(3 + 2a)
(3(3) + 3(2a) + 2a(3) + 2a(2a))(3(3) + 3(2a) + 2a(3) + 2a(2a))(3 + 2a)
(9 + 6a + 6a + 4a²)(9 + 6a + 6a + 4a²)(3 + 2a)
(9 + 12a + 4a²)(9 + 12a + 4a²)(3 + 2a)
(9(9 + 12a + 4a²) + 12a(9 + 12a + 4a²) + 4a²(9 + 12a + 4a²))(3 + 2a)
(9(9) + 9(12a) + 9(4a²) + 12a(9) + 12a(12a) + 12a(4a²) + 4a²(9) + 4a²(12a) + 4a²(4a²)(3 + 2a)
(81 + 108a + 36a² + 108a + 144a² + 36a³ + 36a² + 48a³ + 16a⁴)(3 + 2a)
(81 + 108a + 108a + 36a² + 144a² + 36a² + 36a³ + 48a³ + 16a⁴)(3 + 2a)
(81 + 216a + 216a² + 84a³ + 16a⁴)(3 + 2a)
81(3 + 2a) + 216a(3 + 2a) + 216a²(3 + 2a) + 84a³(3 + 2a) + 16a⁴(3 + 2a)
81(3) + 81(2a) + 216a(3) + 216a(2a) + 216a²(3) + 216a²(2a) + 84a³(3) + 84a³(2a) + 16a⁴(3) + 16a⁴(2a)
324 + 162a + 648a + 432a² + 648a² + 432a³ + 252a³ + 168a⁴ + 48a⁴ + 32a⁵
324 + 810a + 1080a² + 684a³ + 216a⁴ + 32a⁵
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