Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Solve equation 2x^{2}−5x−7 = 0 by using the quadratic formula. Then write 2x^{2}−5x−7 in form of a(x−r_{1})(x−r_{2}).

Sagot :

kate200468
[tex]2x^2+2x-7x-7=2x(x+1)-7(x+1)=(2x-7)(x+1)=\\ \\=2(x-3.5)(x+1)\\ \\2x^2-5x-7=0\ \ \ \Leftrightarrow\ \ \ 2(x-3.5)(x+1)=0\\ \\x-3.5=0\ \ \vee\ \ \ x+1=0\\ \\.\ \ \ \ \ \ \ x=3.5\ \ \ \ \ \ \ \ \ \ \ x=-1[/tex]
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.