Answered

At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Experience the convenience of getting accurate answers to your questions from a dedicated community of professionals. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

an 11 ohm resistor and a 6 ohm resistor are connected in series with a battery. the potential difference across the 6 ohm resistor is 9 volts. find the potential difference across the battery

Sagot :

AL2006

Two resistors in series are often called a 'voltage divider', because the
total voltage divides in proportion to the resistances.

The total resistance in the string across the battery is (11 + 6) = 17 ohms.

-- The full battery voltage appears across 17 ohms.
-- The voltage across the 11-ohms is (11/17) of the battery, and
-- the voltage across the 6-ohms is (6/17) of the battery. 

                                  (6/17) x (B) = 9 volts

Multiply each side by (17/6) :      B = (9 volts) x (17/6)  =  25.5 volts .

By the way, in case you care or are asked . . .

-- The current in the whole series loop is  B/R = 25.5 / 17 = 1.5 Amperes
-- The power drawn from the battery is   B²/R = (25.5)²/17 =  38.25 watts
-- The power dissipated by the 6-ohm resistor is  V²/R = 9²/6 = 13.5 watts
-- The power dissipated by the 11-ohm resistor is I²R = (1.5)² (11) = 24.75W
-- (Check:  13.5W + 24.75W = 38.25W     yay! )
-- If they're just composition units hanging out in the air, then both resistors
are getting quite warm.


Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.