m11i
Answered

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A laboratory procedure calls for making 600.0mL of a 1.1M KNO3 solution. How much KNO3 in grams is needed?

Sagot :

0.6 dm3 x 1.1 dm3
= 0.66 Mols required
If density of water and KNO3 are said to be equal:
then mass = mol x rmm
= 0.66 x 101.1
= 66.73 grams (to 4 sf)
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