Bonte469
Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Please help I looked though all my notes and I couldn't find anything to help me answer this. The question is : A Ferris wheel has a radius of 80 ft. Two particular cars are located such that the central angle between them is 165 degrees. To the nearest tenth, what is the length of the intercept arc between those two cars on the Ferris wheel?

Sagot :

AL2006

The reason you didn't find anything in your High school notes that
can help is that everything you need to answer this one is stuff
you learned in Middle school.

Forget about the big wheel and the sunshine and the cotton candy.
Also, if you're doing any trigonometry or pre-calculus, ignore that too.

-- You have a circle whose radius is  80-ft.

-- Its circumference is (2pi) x (80)  =  160 pi ft.

-- Two points on the circle mark a central angle of 135 degrees.
135 degrees is  ( 135 / 360 ) of a full circle.

-- So the length of the arc between the points is  ( 135 / 360 ) of the
full circumference.

           ( 135 / 360 ) x ( 160 π feet)  =  70.69 feet  (rounded)


bigbrain69

Answer:

230.4

Step-by-step explanation:

% of the circumference for the Intercepted arc = % of the circle of the angle that intercepted it

165 / 360 ≈ 0.4583 = 45.83%

Circumference = 2πr

2π80 = 502.65

502.65*45%=230.4

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.