Answered

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Which sum or difference identity would you use to verify that sin (90° + q) = cos q?

Sagot :

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[tex]\hbox{the sum identity:} \\ \sin(\alpha + \beta)= \sin \alpha \cos \beta + \sin \beta \cos \alpha \\ \\ \sin (90^\circ +q)= \\ \sin 90^\circ \cos q+ \sin q \cos 90^\circ= \\ 1 \times \cos q + \sin q \times 0= \\ \cos q[/tex]
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Answer:

Option B is your answer

Step-by-step explanation:

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