tjmk00
Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Quadratic Equations: ax^2+bx+c=0
Factor first mult. A and C then use the factors from the answer to add to B
1.) 2b^2+10b+12
2.) 3g^2+8g+4
3.) 4x^2+4x-3
4.) 8b^2-5b-10
5.) 6m^2+7m-3
6.) 10d^2+17d-20
Please Answer ASAP Show ALL WORK

Sagot :

apologiabiology
quadratic equaiton is
x=[tex] \frac{-b- \sqrt{b^2-4ac} }{2a} [/tex] or [tex] \frac{-b+ \sqrt{b^2-4ac} }{2a} [/tex]

just subsitute and simplify
I will only do one in detail since it takes some time

so first one2b^2+10b+12
a=2
b=10
c=12
subsitute
x=[tex] \frac{-10- \sqrt{10^2-4(2)(12)} }{2(2)} [/tex] or
[tex] \frac{-10+ \sqrt{10^2-4(2)(12)} }{2(2)} [/tex]
pemdas

[tex] \frac{-10- \sqrt{10^2-4(2)(12)} }{2(2)} [/tex]
do parenthasees or inside exponents
(10^2-4(2)(12) =(100-96)=4
square root of 4=2
(-10-2)/(2 times 2)=-12/4=-3
if -10+square root then
(-10+2)/(2 times 2)=-8/4=-2
answer is
b=-3 or -2


second one
answer is g=-2 or -2/3


3rd
x=-3/2 or 1/2

4th
b=[tex] \frac{5- \sqrt{345} }{16} [/tex] or
[tex] \frac{5+ \sqrt{345} }{16} [/tex]

5th
m=-3/2 or 1/3

6th
d=-5/2 or 4/5


Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.