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Sagot :
[tex]f(x)=3x+2 \\
g(x)=2x-2 \\ \\
(f-g)(x)=f(x)-g(x)=3x+2-(2x-2)=3x+2-2x+2=\\
=x+4 \\ \\
\boxed{(f-g)(x)=x+4}[/tex]
I would assume that you subsitute as usual, but g is negative
(f-g)(x)=(3x+2)-(2x-2)
(f-g)(x)=3x+2-2x+2
(f-g)(x)=x+4
(f-g)(x)=(3x+2)-(2x-2)
(f-g)(x)=3x+2-2x+2
(f-g)(x)=x+4
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