Ajohnson2199
Answered

Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

The probability that a train leaves on time is 0.9. The probability that the train arrives on time and leaves on time is 0.36. What is the probability that the train arrives on time, given that it leaves on time?

0.4
0.9
0.27
0.36

Sagot :

P(arrives on time given leaves on time)=
P(B | A)= P(B n A) / P(A)
= P(A n B) / P(A)
= 0.36 / 0.9
= 0.4
MrRoyal

The probability that the train arrives on time, given that it leaves on time is 0.4

How to determine the probability?

The given parameters are:

  • P(Leave on time) = 0.9
  • P(Arrive and Leave on time) = 0.36

The required probability is calculated using:

P(Arrive on time given that it leaves on time) = P(Arrive and Leave on time)/P(Leave on time)

So, we have:

P(Arrive on time given that it leaves on time) = 0.36/0.9

Evaluate

P(Arrive on time given that it leaves on time) = 0.4

Hence, the probability that the train arrives on time, given that it leaves on time is 0.4

Read more about probability at:

https://brainly.com/question/25870256

#SPJ1

Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.