Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
factor?, if so
if in ax^2+bx+c form then
multiply a and c together
result=z,
find 2 numbers that multiply to get z and add up to get b
so
14=a
-17=b
-6=c
14 times -6=-84
factor to find what 2 numbers add up to -17
-84=
-2, 42
-3,28
-4,21
-6,14
-7,12
add each up
-2, 42=40 nope
-3,28=25 nope
-4,21=17 yes, becase if -21 and 4 then answer
-6,14=8 nope
-7,12=5 nope
split up -17 into -21 and 4
14x^2-21x+4x-6
group
(14x^2-21x)+(4x-6)
undistribute
(7x)(2x-3)+(2)(2x-3)
revesres undistribute (ab+ac=a(b+c) or (a+b)(c)+(a+b)(d)=(a+b)(c+d))
(7x+2)(3x-3) is factore out form
then set it to zero and do th emath because if xy=0 then assume x and/or y=0 so
7x+2=0
subtract 2
7x=-2
divide by 7
x=-2/7
3x-3=0
add 3
3x=3
divide 3
x=1
x=-2/7 or 1
if in ax^2+bx+c form then
multiply a and c together
result=z,
find 2 numbers that multiply to get z and add up to get b
so
14=a
-17=b
-6=c
14 times -6=-84
factor to find what 2 numbers add up to -17
-84=
-2, 42
-3,28
-4,21
-6,14
-7,12
add each up
-2, 42=40 nope
-3,28=25 nope
-4,21=17 yes, becase if -21 and 4 then answer
-6,14=8 nope
-7,12=5 nope
split up -17 into -21 and 4
14x^2-21x+4x-6
group
(14x^2-21x)+(4x-6)
undistribute
(7x)(2x-3)+(2)(2x-3)
revesres undistribute (ab+ac=a(b+c) or (a+b)(c)+(a+b)(d)=(a+b)(c+d))
(7x+2)(3x-3) is factore out form
then set it to zero and do th emath because if xy=0 then assume x and/or y=0 so
7x+2=0
subtract 2
7x=-2
divide by 7
x=-2/7
3x-3=0
add 3
3x=3
divide 3
x=1
x=-2/7 or 1
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.