Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
There is a maximum possible of 2 solutions since this is a polynomial (with a power of 2).
I'm not sure what the easiest way is to determine whether the solutions are real or complex, but I do know of a way that is simple enough to be performed by you . . .
Use the quadratic formula (this calculates the roots of a quadratic equation):
x₁ = [-b + √(b² - 4ac)]/(2a)
x₂ = [-b - √(b² - 4ac)]/(2a)
where:
y = ax² + bx + c
y = 3x² - 5x - 5
so . . .
a = +3
b = -5
c = -5
plug & chug and you get . . .
x₁ = [-3 + √(85)]/(6)
x₂ = [-3 - √(85)]/(6)
since the value under the square root sign is positive (i.e. √(85)), the roots x₁ & x₂ will be positive, and thus they'll have real solutions (note: if it was √(-85), the solution would involve a complex number, so it would not be a real solution)
. . . answer is . . . (b) two
I'm not sure what the easiest way is to determine whether the solutions are real or complex, but I do know of a way that is simple enough to be performed by you . . .
Use the quadratic formula (this calculates the roots of a quadratic equation):
x₁ = [-b + √(b² - 4ac)]/(2a)
x₂ = [-b - √(b² - 4ac)]/(2a)
where:
y = ax² + bx + c
y = 3x² - 5x - 5
so . . .
a = +3
b = -5
c = -5
plug & chug and you get . . .
x₁ = [-3 + √(85)]/(6)
x₂ = [-3 - √(85)]/(6)
since the value under the square root sign is positive (i.e. √(85)), the roots x₁ & x₂ will be positive, and thus they'll have real solutions (note: if it was √(-85), the solution would involve a complex number, so it would not be a real solution)
. . . answer is . . . (b) two
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.
