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What is the area of a square with a side of 8x^7 y^3

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TSO
Area of a square with side s is [tex]\sf{s^2}[/tex]

In your question, the side or s is: [tex]\sf{8x^7y^3}[/tex]

And so the area of a square with that side length would be:

[tex]\sf{(8x^7y^3)^2}[/tex]

And using this formula: [tex]\sf{(a^b)^c =a^{b\times c}}[/tex]

We get that the area is:

[tex]\sf{(8x^7y^3)^2 = 8^2 x^{7\times 2} y^{3\times 2}}[/tex]

And simplifying that we get the final answer as:

[tex]\huge{\boxed{\bf{Area=64x^{14}y^{6}}}}[/tex]
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