Marcia571
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please help How much heat does it take to raise the temperature of 9.0 kg of wood from 12C to 97C? The specific heat of wood is 1.68 kJ/(kgC). Use Q = mc(Tf - Ti). A. 760 kJ B. 1300 kJ C. 180 kJ D. 1500 kJ

Sagot :

AstronautA
Q=mc(Tf-Ti)
   = (9Kg)(1.68 KJ/KgC)(97-12)
   = 1285.2 KJ
   ~ 1300 KJ

Answer:

[tex]Q = 1300 kJ[/tex]

Explanation:

As we know that heat require to change the temperature of the object is given as

[tex]Q = mC \Delta T[/tex]

here we know that

m = mass = 9 kg

C = 1.68 kJ/kg

[tex]\Delta T = 97 - 12[/tex]

[tex]\Delta T = 85 degree C[/tex]

now from above formula we will have

[tex]Q = 9\times 1.68 \times 10^3 \times 85[/tex]

[tex]Q = 1300 kJ[/tex]

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