Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
So. Allow me to justify what i just did.
First line: by definition, tangent in sine/cosine, and cotangent is the reciprocal of that.
Second line: You have to multiply by ([tex] \frac{sin cos}{sincos} [/tex]) to get a common denominator, so you get the second line.
Third line: Canceling stuff out. to get that.
Fourth line: Adding them together since they now have common denominators.
Fifth line: By terms of the pythagorean identity, [tex] sin^{2} [/tex]+[tex] cos^{2} [/tex]=1. so that is equal to the right side.
Thus verified.
First line: by definition, tangent in sine/cosine, and cotangent is the reciprocal of that.
Second line: You have to multiply by ([tex] \frac{sin cos}{sincos} [/tex]) to get a common denominator, so you get the second line.
Third line: Canceling stuff out. to get that.
Fourth line: Adding them together since they now have common denominators.
Fifth line: By terms of the pythagorean identity, [tex] sin^{2} [/tex]+[tex] cos^{2} [/tex]=1. so that is equal to the right side.
Thus verified.
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.