Meh123
Answered

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(X to the -3/2 power) to the 4/3 power

Sagot :

[tex](x^{-\frac{3}{2}})^{\frac{4}{3}} = (\frac{1}{x^\frac{3}{2}})^{\frac{4}{3} = \frac{(1)^{\frac{4}{3}}}{(x^{\frac{3}{2}})^{\frac{4}{3}}} = \frac{1}{x^{2}} [/tex]