Troubled
Answered

At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

How do you solve 4x squared - 12x = 7 (ALGEBRAICALLY)

Sagot :

naǫ
[tex]4x^2-12x=7 \\ 4x^2-12x-7=0 \\ \\ a=4 \\ b=-12 \\ c=-7 \\ b^2-4ac=(-12)^2-4 \times 4 \times (-7)=144+112=256 \\ \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}=\frac{-(-12) \pm \sqrt{256}}{2 \times 4}=\frac{12 \pm 16}{2 \times 4}=\frac{4(3 \pm 4)}{2 \times 4}=\frac{3 \pm 4}{2} \\ x=\frac{3-4}{2} \ \lor \ x=\frac{3+4}{2} \\ x=-\frac{1}{2} \ \lor \ x=\frac{7}{2} \\ \\ \boxed{x=-\frac{1}{2} \hbox{ or } x=\frac{7}{2}}[/tex]
0000000
[tex]\rm 4x^2-12x=7 \\ \\ 4x^2-12x-7=0 \\ \\ 4x^2+2x-14x-7=0 \\ \\ 2x(2x+1)-7(2x+1)=0 \\ \\ (2x+1)(2x-7)=0 \\ \\ I.~2x+1=0 \longrightarrow \bold{x=-\frac12} \\ ~~~~~~~~~~~~~~or \\ \\ II.~2x-7=0 \longrightarrow \bold{x=\frac72}[/tex]
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.