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A battery manufacturer randomly tests 500 batteries and finds that 3 are defective.
How many defective batteries would be expected in a shipment of 12,000 batteries?
A.120
B.72
C.60
D.36


Sagot :

(3/500)*(12,000) = 72 batteries . . . answer is B) 72
If you set up the problem and put 500 / 3 = 12,000 / x, you could cross multiply. 12,000 times 3 = 500 times x. 
36,000 = 500x Now divide both sides by 500.
72 = x
The answer is B.72!