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Sagot :
I think: C. 109.9 inches;
Considering that the entire circumference is [tex]2 \pi r[/tex] a semicircle should be only: [tex] \pi r=3.14*35=109.9 in[/tex]
Considering that the entire circumference is [tex]2 \pi r[/tex] a semicircle should be only: [tex] \pi r=3.14*35=109.9 in[/tex]
If it were a complete circle, its circumference would be
(π) x (diameter) = (π) x (2R) = 70 π inches .
Since it's only half of the circle, the length of the curved part is
70 π / 2 = 35 π = 109.9 inches .
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