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Sagot :
[tex]A=wl \Rightarrow
l=\frac{A}{w}[/tex]
l - length, A - area, w - width
[tex]A=x^3-2x-4 \\ w=x-2 \\ \\ l=\frac{x^3-2x-4}{x-2}=\frac{x^3-2x^2+2x^2-4x+2x-4}{x-2}=\frac{x^2(x-2)+2x(x-2)+2(x-2)}{x-2}=\\ =\frac{(x^2+2x+2)(x-2)}{x-2}=x^2+2x+2[/tex]
The answer is D.
l - length, A - area, w - width
[tex]A=x^3-2x-4 \\ w=x-2 \\ \\ l=\frac{x^3-2x-4}{x-2}=\frac{x^3-2x^2+2x^2-4x+2x-4}{x-2}=\frac{x^2(x-2)+2x(x-2)+2(x-2)}{x-2}=\\ =\frac{(x^2+2x+2)(x-2)}{x-2}=x^2+2x+2[/tex]
The answer is D.
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