Answered

Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

The length of a rectangular mural is 2ft. more than three times the width the area is 165 sq. ft. Find the Width And Length

Sagot :

Cam943
We know that the formula for the area of a rectangle is: 

[tex]A=lw[/tex] 

We know that the area is 165. Now we need to solve for the dimensions. 

Let the width of the rectangle be "[tex]x[/tex]"

Then the length of the rectangle is [tex]3x+2[/tex] 

Substitute. 

[tex](3x+2)(x)=156[/tex] 

Multiply the terms. 

[tex]3x^2+2x=156[/tex] 

Bring the 156 over. 

[tex]3x^2+2x-156=0[/tex] 

We have to use the quadratic formula to solve this now. Let us restate it: 

[tex]x= \frac{-b± \sqrt{b^2-4ac} }{2a} [/tex]

Now I'm going to fast forward this because all the rest is boring stuff and substitution. The answer is: 

[tex] \frac{ \sqrt{469}-1 }{3} [/tex]

Since we cannot have a negative answer, we must cancel out the other answer, which I did not include. 

Hope this helped! :) 

~Cam943, Junior Moderator
jydclix
l×b=area
l=2+3b
2+3b ×b=165
3b²=163
b²=54.3
b=√54.3
b=7.37 or 7.4=7
b=7ft
l=2+3(7.4)
l=2+ 22.2
l=24.2=24
l=24ft
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.