Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

How do you do,
csc2x-cot2x = tanx


Sagot :

[tex]csc2x-cot2x=tanx \\ \\ (\frac{1}{2}cscxsecx) -( \frac{cotx-tanx}{2} )=tanx \\ \\ (\frac{cscxsecx}{2}) -( \frac{cotx-tanx}{2} )=tanx \\ \\ (\frac{ \frac{1}{sinx} \frac{1}{cosx} }{2}) -( \frac{cotx-tanx}{2} )=tanx \\ \\ (\frac{1}{2(sinxcosx)}) -( \frac{cotx-tanx}{2} )=tanx \\ \\ (\frac{1}{2(sinxcosx)}) -( \frac{(sinxcosx)*cotx-tanx}{2*(sinxcosx)} )=tanx \\ \\ \frac{1-(cos^2x-sin^2x)}{2(sinxcosx)} =tanx \\ \\ \frac{1-cos^2+sin^2x}{2(sinxcosx)}=tanx [/tex]

[tex]\frac{sin^2x+sin^2x}{2(sinxcosx)} =tanx \\ \\ \frac{1-cos2x}{sin2x} =tanx \\ \\ \frac{sin2x}{cos2x+1}=tanx \\ \\ tanx=tanx [/tex]


Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.