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50 grams of acetic acid C2H4O2 are dissolved in 200 g of water. Calculate the weight % and mole fraction of the acetic acid in the solution

Sagot :

Scryt
[tex]50g[/tex]   [tex]of[/tex]   [tex] C_2H_4O_2[/tex]   [tex]in[/tex]   [tex] 200g[/tex]    [tex]H_2O[/tex]

so:

[tex] \frac{50}{200+50}+100\%= \frac{50*100}{250}\%=20\%[/tex]

[tex]MW of acid = 2*C+4*H+2*O = 2*12+4*1+2*16=[/tex]

[tex]=24+4+32=60g/mol[/tex]

so:

[tex]\frac{50g}{60g/mol}\approx0.83moles[/tex]

it means that

in [tex]50g[/tex] of acid there is [tex]\approx0.83[/tex]moles of acid

[tex]MW of H_2O = 2*H+O=2*1+16=2+16=18g/mol[/tex]

so:

[tex]\frac{200g}{18g/mol}\approx11.11moles[/tex]

it means that:

in [tex]200g[/tex] of water there is [tex]\approx11.11[/tex]moles of water

therefore:

[tex] \frac{0.83mol}{11.11mol+0.83mol}= \frac{0.83mol}{11.94mol}=0.069[/tex]

So your answers are:

[tex]20\%[/tex]

and the mole fraction is:

[tex]0.069[/tex]
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