Answered

Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

If -nx^3 + tx + c = 0, what is x equal to?

Never mind, found it. 

Sagot :

kate200468
[tex] -nx^3 + tx + c = 0\ /:(-n)\ \ \ \wedge\ \ \ n \neq 0\\ \\x^3- \frac{t}{n} x-\frac{c}{n}=0\\ \\\Delta=(- \frac{t}{n})^3+(-\frac{c}{n})^2= \frac{-t^3}{n^3} + \frac{c^2}{n^2} = \frac{-t^3+n\cdot c^2}{n^3} \\ \\\Delta>0\ \ \Rightarrow\ \ \ x= \sqrt[3]{ \frac{c}{2n}- \sqrt\Delta} } +\sqrt[3]{ \frac{c}{2n}+ \sqrt\Delta} \\ \\\Delta=0\ \ \ \Rightarrow\ \ \ x_1=\sqrt[3]{ \frac{c}{2n}},\ \ \ \ x_2=-2\sqrt[3]{ \frac{c}{2n}}\\ \\\Delta<0\ \ \ \Rightarrow\ \ \ there\ is\ no\ solution\ for\ x\in R[/tex]
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.