Answered

Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

If -nx^3 + tx + c = 0, what is x equal to?

Never mind, found it. 

Sagot :

kate200468
[tex] -nx^3 + tx + c = 0\ /:(-n)\ \ \ \wedge\ \ \ n \neq 0\\ \\x^3- \frac{t}{n} x-\frac{c}{n}=0\\ \\\Delta=(- \frac{t}{n})^3+(-\frac{c}{n})^2= \frac{-t^3}{n^3} + \frac{c^2}{n^2} = \frac{-t^3+n\cdot c^2}{n^3} \\ \\\Delta>0\ \ \Rightarrow\ \ \ x= \sqrt[3]{ \frac{c}{2n}- \sqrt\Delta} } +\sqrt[3]{ \frac{c}{2n}+ \sqrt\Delta} \\ \\\Delta=0\ \ \ \Rightarrow\ \ \ x_1=\sqrt[3]{ \frac{c}{2n}},\ \ \ \ x_2=-2\sqrt[3]{ \frac{c}{2n}}\\ \\\Delta<0\ \ \ \Rightarrow\ \ \ there\ is\ no\ solution\ for\ x\in R[/tex]
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.