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Sagot :
Since you rolled 60 twos and 66 threes out of 360 times this experimental probability is (60+66)/360=126/360=0,35 which is c)
Answer: c) 0.35
Step-by-step explanation:
Let A be an event of rolling a two and B be an event of rolling a three.
Then the probability of rolling a two is given by :-
[tex]\text{P(2)}=\dfrac{60}{360}=\dfrac{1}{6}[/tex]
Then the probability of rolling a three is given by :-
[tex]\text{P(3)}=\dfrac{66}{360}=\dfrac{11}{60}[/tex]
Now, the experimental probability of rolling a two or a three is given by :-
[tex]\text{P(2)}+\text{P(3)}\\\\=\dfrac{1}{6}+\dfrac{11}{60}\\\\=\dfrac{10+11}{60}\\\\=\dfrac{21}{60}=0.35[/tex]
Hence, the  experimental probability of rolling a two or a three is 0.35 .
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